(20-5x)/(6x^2-24x)

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Solution for (20-5x)/(6x^2-24x) equation: 


D( x )

6*x^2-(24*x) = 0

6*x^2-(24*x) = 0

6*x^2-(24*x) = 0

6*x^2-24*x = 0

6*x^2-24*x = 0

DELTA = (-24)^2-(0*4*6)

DELTA = 576

DELTA > 0

x = (576^(1/2)+24)/(2*6) or x = (24-576^(1/2))/(2*6)

x = 4 or x = 0

x in (-oo:0) U (0:4) U (4:+oo)

(20-(5*x))/(6*x^2-(24*x)) = 0

(20-5*x)/(6*x^2-24*x) = 0

6*x^2-24*x = 0

6*x*(x-4) = 0

x-4 = 0 // + 4

x = 4

6*x*(x-4) = 0

(20-5*x)/(6*x*(x-4)) = 0

20-5*x = 0 // - 20

-5*x = -20 // : -5

x = -20/(-5)

x = 4

x in { 4} 

x belongs to the empty set

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